-3x^2-6x^2+7x+14=O

Solution for -3x^2-6x^2+7x+14=O equation:

-3x^2-6x^2+7x+14=

We move all terms to the left:

-3x^2-6x^2+7x+14-()=0

We add all the numbers together, and all the variables

-9x^2+7x=0

a = -9; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-9)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-9}=\frac{-14}{-18}
=7/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-9}=\frac{0}{-18}
=0
$